# How many necklaces are in 6 beads?

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In how many ways can 6 different beads be arranged to form a necklace? – Quora. When the necklace is unclasped and laid out with its ends separated, there are 6! = 720 distinct ways (permutations) to arrange the 6 different beads.

## How many necklaces can you make with 6 beads of 3 colors?

the answer is 60, but how? There are 6 beads in that necklace and each one is a different color. Identify the colors by the codes 1, 2, 3, 4, 5, and 6.

## How many ways can 6 beads be arranged in a string?

=6! =720. Because there are 6 choices for the first bead, five for the second, etc.

## How many necklaces can you make with 8 beads of colors?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

## How many different necklaces can be assembled if we are to use 5 beads of different colors?

The correct answer is 2952 .

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## How many ways can you make a bracelet with 5 different beads?

My answer is : There are possible (n-1)!/2 bracelets for n distinct colors, like in our case. Thus for n=5, there are possible 4!/2=12 different bracelets.

## How many ways can 8 keys be arranged on a keyring?

Eight keys can be arranged 40320 ways on a key ring.

## How many ways can you order 3 things?

= 5*4*3*2*1 = 120. Therefore, the number of ways in which the 3 letters can be arranged, taken all a time, is 3! = 3*2*1 = 6 ways.

## How many ways can 7 keys be arranged in a key ring?

There are 720 ways to arrange 7 keys on a circle.

## How many different necklaces are formed?

How many different necklaces can be formed with 6 white and 5 red beads? Since total number of beads is 11 according to me it should be 11! 6! 5! but correct answer is 21.

## How many bracelets can be made by stringing 9 different colored beads together?

by stringing together 9 different coloured beads one can make 9! (9 factorial ) bracelet. 9! = 9×8×7×6×5×4×3×2×1 = 362880 ways.

## How many ways can 10 different colored beads be treated on a string?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.